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![$I\subset S=K[x_1,\ldots,x_n]$](img3.png){kind=small}
be a lexsegment edge ideal or the Alexander dual of such an ideal.
In both cases it turns out that
the arithmetical rank of 
is equal to the projective dimension of 
Key Words: Arithmetical rank, projective dimension, regularity, edge ideals, squarefree lexsegment ideals, Alexander dual.
2000 Mathematics Subject Classification: Primary: 13F55;
Secondary: 13A15, 55U10.
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